What is f(x)(sqrt(2))=x^2+2 ?

The solution to f(x)(sqrt(2))=x^2+2 is Parabola with (h,k)=(0,sqrt(2)),p= 1/(2sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)(sqrt(2))=x^2+2

f (x) (2) = x^{2} + 2

(h, k) = (0, 2), p = \frac{1}{2 2}

Solution steps

y 2 = x^{2} + 2

Rewrite

y 2 = x^{2} + 2

in the standard form:

4 \cdot \frac{1}{2 2} (y - 2) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 2), p = \frac{1}{2 2}

f (x) = x^{2} - 1.5 f (x) + 3

y - 2 y - 3 y = 4 x^{2} + x - 5

(y + 2)^{2} = - 16 (x - 1)

x^{2} + 14 x - 2 y + 53 = 0

y = - x^{2} + 12 x - 35

What is f(x)(sqrt(2))=x^2+2 ?
The solution to f(x)(sqrt(2))=x^2+2 is Parabola with (h,k)=(0,sqrt(2)),p= 1/(2sqrt(2))