What is (x^2)/(49)+(y^2)/(16)=1 ?

The solution to (x^2)/(49)+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=7,b=4

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(x^2)/(49)+(y^2)/(16)=1

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 7, b = 4

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 4

\frac{( y - 6 ) ^{2}}{64} - \frac{( x - 8 ) ^{2}}{36} = 1

9 x^{2} - 9 y^{2} + 18 x + 36 y = 63

f (x) = x^{2} + 8 x + 12

\frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

x^{2} = 28 y

What is (x^2)/(49)+(y^2)/(16)=1 ?
The solution to (x^2)/(49)+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=7,b=4