What is 18x^2+1/6 r(x)=10 ?

The solution to 18x^2+1/6 r(x)=10 is Parabola with (h,k)=(0,60),p=-1/432

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18x^2+1/6 r(x)=10

18 x^{2} + \frac{1}{6} r (x) = 10

(h, k) = (0, 60), p = - \frac{1}{432}

Solution steps

18 x^{2} + \frac{1}{6} y = 10

Rewrite

18 x^{2} + \frac{1}{6} y = 10

in the standard form:

4 (- \frac{1}{432}) (y - 60) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 60), p = - \frac{1}{432}

\frac{3 y ^{(2)} - 30 y + 2 x + ( 101 )}{( 2 )} = 0

(y + 2)^{2} = 20 (x - 3)

(x + 3)^{2} = 12 (y + 5)

y - 5 x^{2} = 2 x - 6

4 x^{2} - 9 y - 36 = 0

What is 18x^2+1/6 r(x)=10 ?
The solution to 18x^2+1/6 r(x)=10 is Parabola with (h,k)=(0,60),p=-1/432