What is x^2-12x-4y+20=0 ?

The solution to x^2-12x-4y+20=0 is Parabola with (h,k)=(6,-4),p=1

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x^2-12x-4y+20=0

x^{2} - 12 x - 4 y + 20 = 0

(h, k) = (6, - 4), p = 1

Solution steps

x^{2} - 12 x - 4 y + 20 = 0

Rewrite

x^{2} - 12 x - 4 y + 20 = 0

in the standard form

4 \cdot 1 \cdot (y - (- 4)) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, - 4), p = 1

x^{2} - 8 x - 4 y = 0

x^{2} + (- 14) x + 12 y = 36

x^{2} = 8 y + 2

x, 2 q (x)^{2} = - 200 + x

f, ff (7) = - 2 x - 1

What is x^2-12x-4y+20=0 ?
The solution to x^2-12x-4y+20=0 is Parabola with (h,k)=(6,-4),p=1