What is 2x^2-8*(-6)y+10=0 ?

The solution to 2x^2-8*(-6)y+10=0 is Parabola with (h,k)=(0,-5/24),p=-6

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2x^2-8*(-6)y+10=0

2 x^{2} - 8 \cdot (- 6) y + 10 = 0

(h, k) = (0, - \frac{5}{24}), p = - 6

Solution steps

2 x^{2} - 8 (- 6) y + 10 = 0

Rewrite

2 x^{2} - 8 (- 6) y + 10 = 0

in the standard form:

4 (- 6) (y - (- \frac{5}{24})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{5}{24}), p = - 6

(x - h)^{2} = 4 a y

y = x^{2} \cdot 0.5

- 8 x^{2} - 6 v = - 9

x^{2} = 20 (y - 5)

x^{2} + 5 y = 9

What is 2x^2-8*(-6)y+10=0 ?
The solution to 2x^2-8*(-6)y+10=0 is Parabola with (h,k)=(0,-5/24),p=-6