What is y(y+1)/(x+0)=3 ?

The solution to y(y+1)/(x+0)=3 is Parabola with (h,k)=(-1/12 ,-1/2),p= 3/4

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y(y+1)/(x+0)=3

y \frac{y + 1}{x + 0} = 3

(h, k) = (- \frac{1}{12}, - \frac{1}{2}), p = \frac{3}{4}

Solution steps

y \frac{y + 1}{x + 0} = 3

Rewrite

y \frac{y + 1}{x + 0} - 3 = 0

in the standard form

4 \cdot \frac{3}{4} (x - (- \frac{1}{12})) = (y - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{12}, - \frac{1}{2}), p = \frac{3}{4}

f (x) = x^{2} + 12 x + 27

5 y^{2} - 35 x - 40 x - 25 = 0

y^{2} + 12 y - 5 x + 16 = 0

(x - 5)^{(2)} = - 8 (y - 3)

3 x^{2} - 8 y = 0

What is y(y+1)/(x+0)=3 ?
The solution to y(y+1)/(x+0)=3 is Parabola with (h,k)=(-1/12 ,-1/2),p= 3/4