What is 3x^2-2x+k(x)-2=0 ?

The solution to 3x^2-2x+k(x)-2=0 is Parabola with (h,k)=(1/3 , 7/3),p=-1/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2-2x+k(x)-2=0

3 x^{2} - 2 x + k (x) - 2 = 0

(h, k) = (\frac{1}{3}, \frac{7}{3}), p = - \frac{1}{12}

Solution steps

3 x^{2} - 2 x + y - 2 = 0

Rewrite

3 x^{2} - 2 x + y - 2 = 0

in the standard form

4 (- \frac{1}{12}) (y - \frac{7}{3}) = (x - \frac{1}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{3}, \frac{7}{3}), p = - \frac{1}{12}

(y - 3)^{2} = 10 (x - 2)

x^{2} - 4 + 2 y = 0

\frac{y}{x} = \frac{x}{5}

- 3 x^{2} + 12 x - y - 13 = 0

(y - 1)^{2} = 2 (x - 1)

What is 3x^2-2x+k(x)-2=0 ?
The solution to 3x^2-2x+k(x)-2=0 is Parabola with (h,k)=(1/3 , 7/3),p=-1/12