What is 5x^2+7x-k(x)=0 ?

The solution to 5x^2+7x-k(x)=0 is Parabola with (h,k)=(-7/10 ,-49/20),p= 1/20

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5x^2+7x-k(x)=0

5 x^{2} + 7 x - k (x) = 0

(h, k) = (- \frac{7}{10}, - \frac{49}{20}), p = \frac{1}{20}

Solution steps

5 x^{2} + 7 x - y = 0

Rewrite

5 x^{2} + 7 x - y = 0

in the standard form

4 \cdot \frac{1}{20} (y - (- \frac{49}{20})) = (x - (- \frac{7}{10}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{10}, - \frac{49}{20}), p = \frac{1}{20}

2 x^{2} + 3 y = 10

x, x = \frac{( 3 t ( x ) - 6 ) ^{2}}{3}

4 x^{2} - 12 x + q (x) = 0

x = y^{2} - 9 x + 3

(1 - x)^{2} + (2 - y)^{2} - (7 - x)^{2} + y^{2} = 40

What is 5x^2+7x-k(x)=0 ?
The solution to 5x^2+7x-k(x)=0 is Parabola with (h,k)=(-7/10 ,-49/20),p= 1/20