What is 9x^2+18x-3=36r(x) ?

The solution to 9x^2+18x-3=36r(x) is Parabola with (h,k)=(-1,-1/3),p=1

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9x^2+18x-3=36r(x)

9 x^{2} + 18 x - 3 = 36 r (x)

(h, k) = (- 1, - \frac{1}{3}), p = 1

Solution steps

9 x^{2} + 18 x - 3 = 36 y

Rewrite

9 x^{2} + 18 x - 3 = 36 y

in the standard form

4 \cdot 1 \cdot (y - (- \frac{1}{3})) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - \frac{1}{3}), p = 1

x - 5 y < 12 + x^{2}

X^{2} - 2 Y - 1 = 0

2 x - 4 y^{2} + 20 y = 5

12 (x - 1) = (y - 3)^{2}

(y - 3)^{2} = 20 (x + 2)

What is 9x^2+18x-3=36r(x) ?
The solution to 9x^2+18x-3=36r(x) is Parabola with (h,k)=(-1,-1/3),p=1