What is 1/(t+5)= 6/(r^2-25) ?

The solution to 1/(t+5)= 6/(r^2-25) is Parabola with (h,k)=(-55/6 ,0),p= 3/2

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1/(t+5)= 6/(r^2-25)

\frac{1}{t + 5} = \frac{6}{r ^{2} - 25}

(h, k) = (- \frac{55}{6}, 0), p = \frac{3}{2}

Solution steps

\frac{1}{t + 5} = \frac{6}{r ^{2} - 25}

Rewrite

\frac{1}{t + 5} - \frac{6}{r ^{2} - 25} = 0

in the standard form

4 \cdot \frac{3}{2} (t - (- \frac{55}{6})) = (r - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{55}{6}, 0), p = \frac{3}{2}

y^{2} - 8 y + 8 x + 16 = 0

25 = \frac{x}{y ^{2}}

x^{2} - 76 x + 20 y + 50 = 0

x 0.14 x - 0.03 y = 0.48

y - 5 x^{2} = 6

What is 1/(t+5)= 6/(r^2-25) ?
The solution to 1/(t+5)= 6/(r^2-25) is Parabola with (h,k)=(-55/6 ,0),p= 3/2