What is f(x)(x)^{-1}=-8+4/3 x ?

The solution to f(x)(x)^{-1}=-8+4/3 x is Parabola with (h,k)=(3,-12),p= 3/16

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f(x)(x)^{-1}=-8+4/3 x

f (x) (x)^{- 1} = - 8 + \frac{4}{3} x

(h, k) = (3, - 12), p = \frac{3}{16}

Solution steps

y x^{- 1} = - 8 + \frac{4}{3} x

Rewrite

y x^{- 1} + 8 - \frac{4}{3} x = 0

in the standard form

4 \cdot \frac{3}{16} (y - (- 12)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 12), p = \frac{3}{16}

- x^{2} + 6 x + 5 y + 6 = 0

16 y^{2} - x > 0

(x - 7)^{2} = - 6 (y + 7)

- 8 (x - 5) = (y - 4)^{2}

2 \cdot 0.25 π X \cdot 0.25 π = 2 π r^{2} \cdot 0.25 π

What is f(x)(x)^{-1}=-8+4/3 x ?
The solution to f(x)(x)^{-1}=-8+4/3 x is Parabola with (h,k)=(3,-12),p= 3/16