What is 1/12 y^2-1/2 y-13/4 =x ?

The solution to 1/12 y^2-1/2 y-13/4 =x is Parabola with (h,k)=(-4,3),p=3

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1/12 y^2-1/2 y-13/4 =x

\frac{1}{12} y^{2} - \frac{1}{2} y - \frac{13}{4} = x

(h, k) = (- 4, 3), p = 3

Solution steps

\frac{1}{12} y^{2} - \frac{1}{2} y - \frac{13}{4} = x

Rewrite

\frac{1}{12} y^{2} - \frac{1}{2} y - \frac{13}{4} = x

in the standard form

4 \cdot 3 (x - (- 4)) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 3), p = 3

x^{2} - 10 x - 64 y + 89 = 0

x^{2} + 12 x = - \frac{3}{2} y - 39

(x - 2)^{2} = 8 (y - 4)

x^{2} - 10 x - 72 y = - 25 - 72

4 y = 6 x^{2} - 7

What is 1/12 y^2-1/2 y-13/4 =x ?
The solution to 1/12 y^2-1/2 y-13/4 =x is Parabola with (h,k)=(-4,3),p=3