What is f(x)(2/3)^2=3x^2-5x+4 ?

The solution to f(x)(2/3)^2=3x^2-5x+4 is Parabola with (h,k)=(5/6 , 69/16),p= 1/27

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f(x)(2/3)^2=3x^2-5x+4

f (x) (\frac{2}{3})^{2} = 3 x^{2} - 5 x + 4

(h, k) = (\frac{5}{6}, \frac{69}{16}), p = \frac{1}{27}

Solution steps

y (\frac{2}{3})^{2} = 3 x^{2} - 5 x + 4

Rewrite

y (\frac{2}{3})^{2} = 3 x^{2} - 5 x + 4

in the standard form

4 \cdot \frac{1}{27} (y - \frac{69}{16}) = (x - \frac{5}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{6}, \frac{69}{16}), p = \frac{1}{27}

y = - 3 x^{2} + 24 x - 43

y 2 y - 4 x = 4

- y = x^{2} - 6

x^{2} + 76 x + 100 y - 100 = 0

y \geq - x^{2} + 1

What is f(x)(2/3)^2=3x^2-5x+4 ?
The solution to f(x)(2/3)^2=3x^2-5x+4 is Parabola with (h,k)=(5/6 , 69/16),p= 1/27