What is (-y)^2-(y-1)^2=x^2-x^2 ?

The solution to (-y)^2-(y-1)^2=x^2-x^2 is Parabola with (h,k)=(0,0),p= 1/4

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(-y)^2-(y-1)^2=x^2-x^2

(- y)^{2} - (y - 1)^{2} = x^{2} - x^{2}

(h, k) = (0, 0), p = \frac{1}{4}

Solution steps

(- y)^{2} - (y - 1)^{2} = x^{2} - x^{2}

Rewrite

(- y)^{2} - (y - 1)^{2} = x^{2} - x^{2}

in the standard form

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

(y + 3)^{2} = - 5 (x - 1)

x^{2} + 3 y - 4 x = 17

f (x) = - 3 x^{2} + 24 x - 36

y \geq - x^{2} - 1

x = \frac{- 7 y + 4}{1 + 6 x}

What is (-y)^2-(y-1)^2=x^2-x^2 ?
The solution to (-y)^2-(y-1)^2=x^2-x^2 is Parabola with (h,k)=(0,0),p= 1/4