What is -f(x)=4x^2+5x+9 ?

The solution to -f(x)=4x^2+5x+9 is Parabola with (h,k)=(-5/8 ,-119/16),p=-1/16

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-f(x)=4x^2+5x+9

- f (x) = 4 x^{2} + 5 x + 9

(h, k) = (- \frac{5}{8}, - \frac{119}{16}), p = - \frac{1}{16}

Solution steps

- y = 4 x^{2} + 5 x + 9

Rewrite

- y = 4 x^{2} + 5 x + 9

in the standard form

4 (- \frac{1}{16}) (y - (- \frac{119}{16})) = (x - (- \frac{5}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{8}, - \frac{119}{16}), p = - \frac{1}{16}

(x + 3)^{2} = - 24 (y - 1)

f (x) = - 0.99968 (x^{2} - 2.5 x - 0.23808)

x^{2} + 4^{2} - 14 x + 2 y = - 14

(x - 2)^{(2)} = \frac{( 1 )}{2} (y - 1)

12 X^{2} = - 4 Y

What is -f(x)=4x^2+5x+9 ?
The solution to -f(x)=4x^2+5x+9 is Parabola with (h,k)=(-5/8 ,-119/16),p=-1/16