What is the foci (x^2)/(36)-(y^2)/(64)=1 ?

The foci (x^2)/(36)-(y^2)/(64)=1 is (10,0),(-10,0)

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foci (x^2)/(36)-(y^2)/(64)=1

foci

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

(10, 0), (- 10, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 8

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} + 8^{2} : 10

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

x^{2} = - 6 y

y^{2} - 4 y - 4 x = 0

\frac{x ^{2}}{16} + \frac{y ^{2}}{49} = 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

What is the foci (x^2)/(36)-(y^2)/(64)=1 ?
The foci (x^2)/(36)-(y^2)/(64)=1 is (10,0),(-10,0)