What is (x-1/2)^2=8(y+5) ?

The solution to (x-1/2)^2=8(y+5) is Parabola with (h,k)=(1/2 ,-5),p=2

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(x-1/2)^2=8(y+5)

(x - \frac{1}{2})^{2} = 8 (y + 5)

(h, k) = (\frac{1}{2}, - 5), p = 2

Solution steps

(x - \frac{1}{2})^{2} = 8 (y + 5)

Rewrite

(x - \frac{1}{2})^{2} = 8 (y + 5)

in the standard form:

4 \cdot 2 (y - (- 5)) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, - 5), p = 2

x - y^{2} = 10

\frac{( 1 - x )}{( y - 2 )} = \frac{( x + 2 )}{( x - y )}

3 y^{2} + 30 y - x + 71 = 0

(3 y - 6)^{2} = 36 (x - 2)

(y - 3) = - \frac{1}{4} (x + 4)^{2}

What is (x-1/2)^2=8(y+5) ?
The solution to (x-1/2)^2=8(y+5) is Parabola with (h,k)=(1/2 ,-5),p=2