What is 4x^2-2x-f(x)=0 ?

The solution to 4x^2-2x-f(x)=0 is Parabola with (h,k)=(1/4 ,-1/4),p= 1/16

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4x^2-2x-f(x)=0

4 x^{2} - 2 x - f (x) = 0

(h, k) = (\frac{1}{4}, - \frac{1}{4}), p = \frac{1}{16}

Solution steps

4 x^{2} - 2 x - y = 0

Rewrite

4 x^{2} - 2 x - y = 0

in the standard form

4 \cdot \frac{1}{16} (y - (- \frac{1}{4})) = (x - \frac{1}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{4}, - \frac{1}{4}), p = \frac{1}{16}

3 x^{2} + 3 z + 6 = 0

1 - \frac{3 x ^{2} + 5 x}{y} = 0

y^{2} = - 20 (X - 2)

x = - y^{2} - 1

y^{2} - 2 y + 4 x - 7 = 0

What is 4x^2-2x-f(x)=0 ?
The solution to 4x^2-2x-f(x)=0 is Parabola with (h,k)=(1/4 ,-1/4),p= 1/16