What is 4y^2-48x-20y-76=0 ?

The solution to 4y^2-48x-20y-76=0 is Parabola with (h,k)=(-101/48 , 5/2),p=3

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4y^2-48x-20y-76=0

4 y^{2} - 48 x - 20 y - 76 = 0

(h, k) = (- \frac{101}{48}, \frac{5}{2}), p = 3

Solution steps

4 y^{2} - 48 x - 20 y - 76 = 0

Rewrite

4 y^{2} - 48 x - 20 y - 76 = 0

in the standard form

4 \cdot 3 (x - (- \frac{101}{48})) = (y - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{101}{48}, \frac{5}{2}), p = 3

y^{2} - 3 x + 2 y + 1 = 0

x^{2} = 2 x - 2 y

\frac{( x - 10 ) ^{2}}{100} - \frac{y + 3 ^{2}}{36} = 1

x, \frac{104}{x} = \frac{500}{0.03 m ( x ) ^{2}}

x^{2} + 2 x + 4 y = 19

What is 4y^2-48x-20y-76=0 ?
The solution to 4y^2-48x-20y-76=0 is Parabola with (h,k)=(-101/48 , 5/2),p=3