What is the vertices x^2-24x-12 ?

The vertices x^2-24x-12 is Minimum (12,-156)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices x^2-24x-12

vertices

x^{2} - 24 x - 12

Minimum (12, - 156)

Solution steps

y = x^{2} - 24 x - 12

The parabola parameters are:

a = 1, b = - 24, c = - 12

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 24 )}{2 \cdot 1}

Simplify

x_{v} = 12

Plug in

x_{v} = 12

to find the

y_{v}

value

y_{v} = - 156

Therefore the parabola vertex is

(12, - 156)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (12, - 156)

16 x^{2} + 9 y^{2} = 144

- x^{2} + y^{2} = 1

y^{2} - \frac{x ^{2}}{9} = 1

y^{2} = 2 x + 1

x^{2} + 2 y^{2} = 3