What is 3(x+3/4)+3(y-1/2)^2=36 ?

The solution to 3(x+3/4)+3(y-1/2)^2=36 is Parabola with (h,k)=(45/4 , 1/2),p=-1/4

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3(x+3/4)+3(y-1/2)^2=36

3 (x + \frac{3}{4}) + 3 (y - \frac{1}{2})^{2} = 36

(h, k) = (\frac{45}{4}, \frac{1}{2}), p = - \frac{1}{4}

Solution steps

3 (x + \frac{3}{4}) + 3 (y - \frac{1}{2})^{2} = 36

Rewrite

3 (x + \frac{3}{4}) + 3 (y - \frac{1}{2})^{2} = 36

in the standard form:

4 (- \frac{1}{4}) (x - \frac{45}{4}) = (y - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{45}{4}, \frac{1}{2}), p = - \frac{1}{4}

x = - 5 (\frac{y + 9}{4})^{2}

x^{2} - 10 x - 79 y = - 25 - 79

y^{2} - 20 x - 8 y - 24 = 0

(y - 4)^{2} = - 8 (x - 5)

3 x + 6 y^{2} = 0

What is 3(x+3/4)+3(y-1/2)^2=36 ?
The solution to 3(x+3/4)+3(y-1/2)^2=36 is Parabola with (h,k)=(45/4 , 1/2),p=-1/4