What is 3x^2-22x+42+3y-10y=0 ?

The solution to 3x^2-22x+42+3y-10y=0 is Parabola with (h,k)=(11/3 , 5/21),p= 7/12

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3x^2-22x+42+3y-10y=0

3 x^{2} - 22 x + 42 + 3 y - 10 y = 0

(h, k) = (\frac{11}{3}, \frac{5}{21}), p = \frac{7}{12}

Solution steps

3 x^{2} - 22 x + 42 + 3 y - 10 y = 0

Rewrite

3 x^{2} - 22 x + 42 + 3 y - 10 y = 0

in the standard form

4 \cdot \frac{7}{12} (y - \frac{5}{21}) = (x - \frac{11}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{11}{3}, \frac{5}{21}), p = \frac{7}{12}

y^{2} = C x + 3

- 3 x + y^{(2)} = 3

(x + 1)^{2} = 20 (y + 3)

y^{2} = - 2 x + 2

y^{2} = - 2 x + 5

What is 3x^2-22x+42+3y-10y=0 ?
The solution to 3x^2-22x+42+3y-10y=0 is Parabola with (h,k)=(11/3 , 5/21),p= 7/12