What is 1/x+1/(25-x)= 1/z ?

The solution to 1/x+1/(25-x)= 1/z is Parabola with (h,k)=(25/2 , 25/4),p=-25/4

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1/x+1/(25-x)= 1/z

\frac{1}{x} + \frac{1}{25 - x} = \frac{1}{z}

(h, k) = (\frac{25}{2}, \frac{25}{4}), p = - \frac{25}{4}

Solution steps

\frac{1}{x} + \frac{1}{25 - x} = \frac{1}{z}

Rewrite

\frac{1}{x} + \frac{1}{25 - x} - \frac{1}{z} = 0

in the standard form

4 (- \frac{25}{4}) (z - \frac{25}{4}) = (x - \frac{25}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{25}{2}, \frac{25}{4}), p = - \frac{25}{4}

3 x^{2} - y - 4 = 0

3 (x - 4) 2 + 3 y^{2} = 54

i f (x) = 3 x^{2}

\frac{x}{f ( x )} (x) = - \frac{2}{3}

g (x) (2 \cdot 2 - 3) = x^{2} + 1

What is 1/x+1/(25-x)= 1/z ?
The solution to 1/x+1/(25-x)= 1/z is Parabola with (h,k)=(25/2 , 25/4),p=-25/4