What is (13/12-1)3y^2-6y-x=0 ?

The solution to (13/12-1)3y^2-6y-x=0 is Parabola with (h,k)=(-36,12),p=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(13/12-1)3y^2-6y-x=0

(\frac{13}{12} - 1) 3 y^{2} - 6 y - x = 0

(h, k) = (- 36, 12), p = 1

Solution steps

(\frac{13}{12} - 1) \cdot 3 y^{2} - 6 y - x = 0

Rewrite

(\frac{13}{12} - 1) \cdot 3 y^{2} - 6 y - x = 0

in the standard form

4 \cdot 1 \cdot (x - (- 36)) = (y - 12)^{2}

Therefore parabola properties are:

(h, k) = (- 36, 12), p = 1

x^{2} - 6 x - 4 y + 17 = 0

y > x^{2} - 4 x + 2

y - 8 = (6 - 10 x) (x - 1)

3 x + 2 yy = - 1

y - 2 = x^{2} + 4

What is (13/12-1)3y^2-6y-x=0 ?
The solution to (13/12-1)3y^2-6y-x=0 is Parabola with (h,k)=(-36,12),p=1