What is x^2+4y^2-4x=0 ?

The solution to x^2+4y^2-4x=0 is Ellipse with (h,k)=(2,0),a=2,b=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+4y^2-4x=0

x^{2} + 4 y^{2} - 4 x = 0

(h, k) = (2, 0), a = 2, b = 1

Solution steps

x^{2} + 4 y^{2} - 4 x = 0

Rewrite

x^{2} + 4 y^{2} - 4 x = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 0), a = 2, b = 1

4 x^{2} + 9 y^{2} = 36

3 x^{2} + 2 y^{2} + 6 x - 4 y + 5 = 18

f (x) = x^{2} + 8 x + 15

y^{2} = - 20 x

f (x) = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

What is x^2+4y^2-4x=0 ?
The solution to x^2+4y^2-4x=0 is Ellipse with (h,k)=(2,0),a=2,b=1