What is f(65)= 1/400*(v-20)^2+2 ?

The solution to f(65)= 1/400*(v-20)^2+2 is Parabola with (h,k)=(2/65 ,20),p=6500

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f(65)= 1/400*(v-20)^2+2

f (65) = \frac{1}{400} \cdot (v - 20)^{2} + 2

(h, k) = (\frac{2}{65}, 20), p = 6500

Solution steps

f \cdot 65 = \frac{1}{400} (v - 20)^{2} + 2

Rewrite

f \cdot 65 = \frac{1}{400} (v - 20)^{2} + 2

in the standard form:

4 \cdot 6500 (f - \frac{2}{65}) = (v - 20)^{2}

Therefore parabola properties are:

(h, k) = (\frac{2}{65}, 20), p = 6500

4 x^{2} + 2 x 78 = o

x^{2} + 3 y + 2 = 0

(y + 3)^{2} = 4 (x + 5)

x = y^{2} - 10 y + 34

y = 2 (x - 5) (x - 1)

What is f(65)= 1/400*(v-20)^2+2 ?
The solution to f(65)= 1/400*(v-20)^2+2 is Parabola with (h,k)=(2/65 ,20),p=6500