What is x^2=sqrt(8/27)y-3 ?

The solution to x^2=sqrt(8/27)y-3 is Parabola with (h,k)=(0,(9sqrt(3))/(2sqrt(2))),p= 1/(3sqrt(6))

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x^2=sqrt(8/27)y-3

x^{2} = \frac{8}{27} y - 3

(h, k) = (0, \frac{9 3}{2 2}), p = \frac{1}{3 6}

Solution steps

x^{2} = \frac{8}{27} y - 3

Rewrite

x^{2} = \frac{8}{27} y - 3

in the standard form:

4 \cdot \frac{1}{3 6} (y - \frac{9 3}{2 2}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{9 3}{2 2}), p = \frac{1}{3 6}

y = 8 y^{2} + 2 x - 6

f (x) = 2 x^{2} + 2 x - 60

x^{2} - 6 x + 8 y + 17 = 0

(1 - x) \frac{a}{b} = y^{2}

0 = y - \frac{9 x ^{2}}{2}

What is x^2=sqrt(8/27)y-3 ?
The solution to x^2=sqrt(8/27)y-3 is Parabola with (h,k)=(0,(9sqrt(3))/(2sqrt(2))),p= 1/(3sqrt(6))