What is (x+5)+(y-6)^{(2)}=4 ?

The solution to (x+5)+(y-6)^{(2)}=4 is Parabola with (h,k)=(-1,6),p=-1/4

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(x+5)+(y-6)^{(2)}=4

(x + 5) + (y - 6)^{(2)} = 4

(h, k) = (- 1, 6), p = - \frac{1}{4}

Solution steps

x + 5 + (y - 6)^{2} = 4

Rewrite

x + 5 + (y - 6)^{2} = 4

in the standard form:

4 (- \frac{1}{4}) (x - (- 1)) = (y - 6)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 6), p = - \frac{1}{4}

4 - (3 - 2) - 4 x = y^{2}

x^{2} - 10 x - 20 y + 25 = 0

(x + 3) = (y - 1)^{2}

y - 3 x + 4 x^{2} = 7

(x - 3)^{2} = - 8 y

What is (x+5)+(y-6)^{(2)}=4 ?
The solution to (x+5)+(y-6)^{(2)}=4 is Parabola with (h,k)=(-1,6),p=-1/4