What is (y+2)^2=3(x-11/3) ?

The solution to (y+2)^2=3(x-11/3) is Parabola with (h,k)=(11/3 ,-2),p= 3/4

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(y+2)^2=3(x-11/3)

(y + 2)^{2} = 3 (x - \frac{11}{3})

(h, k) = (\frac{11}{3}, - 2), p = \frac{3}{4}

Solution steps

(y + 2)^{2} = 3 (x - \frac{11}{3})

Rewrite

(y + 2)^{2} = 3 (x - \frac{11}{3})

in the standard form:

4 \cdot \frac{3}{4} (x - \frac{11}{3}) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (\frac{11}{3}, - 2), p = \frac{3}{4}

(y + 2)^{2} = 16 (x + 2)

15 = \frac{\frac{\frac{x}{5 + R ( x )}}{R ( x )}}{15}

(x - 2)^{2} + (y - 0)^{2} = (x + 3)^{2}

y^{2} + 16 x - 6 y - 7 = 0

\frac{f ( x )}{2 x} \leq \frac{x ^{2} + 1}{2 x}

What is (y+2)^2=3(x-11/3) ?
The solution to (y+2)^2=3(x-11/3) is Parabola with (h,k)=(11/3 ,-2),p= 3/4