What is ((2y^2+y)/4)=x ?

The solution to ((2y^2+y)/4)=x is Parabola with (h,k)=(-1/32 ,-1/4),p= 1/2

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((2y^2+y)/4)=x

(\frac{2 y ^{2} + y}{4}) = x

(h, k) = (- \frac{1}{32}, - \frac{1}{4}), p = \frac{1}{2}

Solution steps

\frac{2 y ^{2} + y}{4} = x

Rewrite

\frac{2 y ^{2} + y}{4} = x

in the standard form

4 \cdot \frac{1}{2} (x - (- \frac{1}{32})) = (y - (- \frac{1}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{32}, - \frac{1}{4}), p = \frac{1}{2}

y < x^{2} - x + 4

5 x^{2} - 3 y = 4

x = y^{2} + 4 y - 5

x = y^{2} + 4 y - 7

6 xx + 7 y = 7

What is ((2y^2+y)/4)=x ?
The solution to ((2y^2+y)/4)=x is Parabola with (h,k)=(-1/32 ,-1/4),p= 1/2