What is -1/2 (y-2)^2=(x-2) ?

The solution to -1/2 (y-2)^2=(x-2) is Parabola with (h,k)=(2,2),p=-1/2

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-1/2 (y-2)^2=(x-2)

- \frac{1}{2} (y - 2)^{2} = (x - 2)

(h, k) = (2, 2), p = - \frac{1}{2}

Solution steps

- \frac{1}{2} (y - 2)^{2} = (x - 2)

Rewrite

- \frac{1}{2} (y - 2)^{2} = (x - 2)

in the standard form:

4 (- \frac{1}{2}) (x - 2) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 2), p = - \frac{1}{2}

(x - 2)^{2} = 8 (y + 5)

y \frac{1}{2} y = - \frac{4}{5} x + \frac{7}{10}

x^{2} + x + m (x) = 0

6 x^{2} - y + 3 = 0

(x - 6)^{2} = 1.8 (y - 5)

What is -1/2 (y-2)^2=(x-2) ?
The solution to -1/2 (y-2)^2=(x-2) is Parabola with (h,k)=(2,2),p=-1/2