What is f(x)(x)^{-1}= 1/3 x-2 ?

The solution to f(x)(x)^{-1}= 1/3 x-2 is Parabola with (h,k)=(3,-3),p= 3/4

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f(x)(x)^{-1}= 1/3 x-2

f (x) (x)^{- 1} = \frac{1}{3} x - 2

(h, k) = (3, - 3), p = \frac{3}{4}

Solution steps

y x^{- 1} = \frac{1}{3} x - 2

Rewrite

y x^{- 1} - \frac{1}{3} x + 2 = 0

in the standard form

4 \cdot \frac{3}{4} (y - (- 3)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 3), p = \frac{3}{4}

\frac{9 \cdot 1 0 ^{9} \cdot x \cdot x}{y} = 100

x^{2} - 8 x + 64 = 12 y

- 4 = 4 x^{2} + 6 y

x + 9 = (y - 1)^{2}

0 \geq 0.1 x^{2} - 200 q (x) + 19000

What is f(x)(x)^{-1}= 1/3 x-2 ?
The solution to f(x)(x)^{-1}= 1/3 x-2 is Parabola with (h,k)=(3,-3),p= 3/4