What is y^2+10y+2x-24=0 ?

The solution to y^2+10y+2x-24=0 is Parabola with (h,k)=(49/2 ,-5),p=-1/2

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y^2+10y+2x-24=0

y^{2} + 10 y + 2 x - 24 = 0

(h, k) = (\frac{49}{2}, - 5), p = - \frac{1}{2}

Solution steps

y^{2} + 10 y + 2 x - 24 = 0

Rewrite

y^{2} + 10 y + 2 x - 24 = 0

in the standard form

4 (- \frac{1}{2}) (x - \frac{49}{2}) = (y - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (\frac{49}{2}, - 5), p = - \frac{1}{2}

y \leq (x + 3)^{2} - 2

y = x^{2} + 4 x - 24

(y - 2)^{2} = 6 (x - 1)

f (x) = - x^{2} + 5 - 2

y + 2 = x^{2}

What is y^2+10y+2x-24=0 ?
The solution to y^2+10y+2x-24=0 is Parabola with (h,k)=(49/2 ,-5),p=-1/2