What is the foci (x^2}{36}+\frac{y^2)/4 =1 ?

The foci (x^2}{36}+\frac{y^2)/4 =1 is (4sqrt(2),0),(-4sqrt(2),0)

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foci (x^2}{36}+\frac{y^2)/4 =1

foci

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

(42, 0), (- 42, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} - 2^{2} : 42

(0 + 42, 0), (0 - 42, 0)

Refine

(42, 0), (- 42, 0)

x^{2} + 4 x - 4 y = 0

y^{2} - 4 x = 0

16 x^{2} + y^{2} = 16

y^{2} = 3 x

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

What is the foci (x^2}{36}+\frac{y^2)/4 =1 ?
The foci (x^2}{36}+\frac{y^2)/4 =1 is (4sqrt(2),0),(-4sqrt(2),0)