What is (1/6)(x^2+3x-4)=p(x)6 ?

The solution to (1/6)(x^2+3x-4)=p(x)6 is Parabola with (h,k)=(-3/2 ,-25/144),p=9

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(1/6)(x^2+3x-4)=p(x)6

(\frac{1}{6}) (x^{2} + 3 x - 4) = p (x) 6

(h, k) = (- \frac{3}{2}, - \frac{25}{144}), p = 9

Solution steps

\frac{1}{6} (x^{2} + 3 x - 4) = y \cdot 6

Rewrite

\frac{1}{6} (x^{2} + 3 x - 4) = y \cdot 6

in the standard form

4 \cdot 9 (y - (- \frac{25}{144})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{25}{144}), p = 9

y^{2} + 6 y + 9 = 4 x

(y + 1)^{2} = - (x + 2)

(y)^{2} = 4 a (x - B)

(x + \frac{1}{2})^{2} = 4 (y - 2)

x^{2} - 12 x + 4 y + 24 = 0

What is (1/6)(x^2+3x-4)=p(x)6 ?
The solution to (1/6)(x^2+3x-4)=p(x)6 is Parabola with (h,k)=(-3/2 ,-25/144),p=9