What is 2x^2-9x+7=(x-9/4)^2+y ?

The solution to 2x^2-9x+7=(x-9/4)^2+y is Parabola with (h,k)=(9/4 ,-25/8),p= 1/4

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2x^2-9x+7=(x-9/4)^2+y

2 x^{2} - 9 x + 7 = (x - \frac{9}{4})^{2} + y

(h, k) = (\frac{9}{4}, - \frac{25}{8}), p = \frac{1}{4}

Solution steps

2 x^{2} - 9 x + 7 = (x - \frac{9}{4})^{2} + y

Rewrite

2 x^{2} - 9 x + 7 = (x - \frac{9}{4})^{2} + y

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{25}{8})) = (x - \frac{9}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{4}, - \frac{25}{8}), p = \frac{1}{4}

- x^{2} + 2 x - 4 y = 6

y + 4 = x^{2}

x + y = y^{2} - 3

9 x^{2} - 16 y = 144

- 20 x + y^{2} - 6 y + 49 = 0

What is 2x^2-9x+7=(x-9/4)^2+y ?
The solution to 2x^2-9x+7=(x-9/4)^2+y is Parabola with (h,k)=(9/4 ,-25/8),p= 1/4