What is (3+x)6x+4y=50 ?

The solution to (3+x)6x+4y=50 is Parabola with (h,k)=(-3/2 , 127/8),p=-1/6

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(3+x)6x+4y=50

(3 + x) 6 x + 4 y = 50

(h, k) = (- \frac{3}{2}, \frac{127}{8}), p = - \frac{1}{6}

Solution steps

(3 + x) \cdot 6 x + 4 y = 50

Rewrite

(3 + x) \cdot 6 x + 4 y = 50

in the standard form

4 (- \frac{1}{6}) (y - \frac{127}{8}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{127}{8}), p = - \frac{1}{6}

y = - 0.3 (x - 1.7)^{2} + 19

2 y - 2 = 3 x^{2} + 4 x + 2

h (x) = (x + 1)^{2} + 3

(x + 2) x + (y - 2) = 0

y = 60 x - 2 x^{2}

What is (3+x)6x+4y=50 ?
The solution to (3+x)6x+4y=50 is Parabola with (h,k)=(-3/2 , 127/8),p=-1/6