What is 10x^2-256=300f(x)ind ?

The solution to 10x^2-256=300f(x)ind is Parabola with (h,k)=(0,-(64}{75din}),p=\frac{15din)/2

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10x^2-256=300f(x)ind

10 x^{2} - 256 = 300 f (x) in d

(h, k) = (0, - \frac{64}{75 d in}), p = \frac{15 d in}{2}

Solution steps

10 x^{2} - 256 = 300 y in d

Rewrite

10 x^{2} - 256 = 300 y in d

in the standard form:

4 \cdot \frac{15 d in}{2} (y - (- \frac{64}{75 d in})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{64}{75 d in}), p = \frac{15 d in}{2}

(y + 2)^{2} = 3 x + 1

x^{2} - 10 - 15 y + 21 = 0

y = - \frac{1}{12} (x - 2)^{2} + 2

2 x^{2} - 8 x + y = - 9

b - y = x^{2} + 2

What is 10x^2-256=300f(x)ind ?
The solution to 10x^2-256=300f(x)ind is Parabola with (h,k)=(0,-(64}{75din}),p=\frac{15din)/2