What is 3(x^2-2y)=9(x^2-3y) ?

The solution to 3(x^2-2y)=9(x^2-3y) is Parabola with (h,k)=(0,0),p= 7/8

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3(x^2-2y)=9(x^2-3y)

3 (x^{2} - 2 y) = 9 (x^{2} - 3 y)

(h, k) = (0, 0), p = \frac{7}{8}

Solution steps

3 (x^{2} - 2 y) = 9 (x^{2} - 3 y)

Rewrite

3 (x^{2} - 2 y) - 9 (x^{2} - 3 y) = 0

in the standard form

4 \cdot \frac{7}{8} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{7}{8}

x = 2 y^{2} + 12 y - 14

x = (y + 4)^{2}

x + 12 = y^{2}

y = 80 x - 2 x^{2}

(2 y + 3)^{2} = - 16 (2 x + 1)

What is 3(x^2-2y)=9(x^2-3y) ?
The solution to 3(x^2-2y)=9(x^2-3y) is Parabola with (h,k)=(0,0),p= 7/8