What is 4x^2-3y-8x+6y+1=0 ?

The solution to 4x^2-3y-8x+6y+1=0 is Parabola with (h,k)=(1,1),p=-3/16

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4x^2-3y-8x+6y+1=0

4 x^{2} - 3 y - 8 x + 6 y + 1 = 0

(h, k) = (1, 1), p = - \frac{3}{16}

Solution steps

4 x^{2} - 3 y - 8 x + 6 y + 1 = 0

Rewrite

4 x^{2} - 3 y - 8 x + 6 y + 1 = 0

in the standard form

4 (- \frac{3}{16}) (y - 1) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 1), p = - \frac{3}{16}

x^{2} + 10000 s + 500000 = 0

(x + 7)^{2} = (y + 2)

x^{2} - 9 m (x) = 0

3 x^{2} - 18 y = 0

x^{2} + x = 3 y

What is 4x^2-3y-8x+6y+1=0 ?
The solution to 4x^2-3y-8x+6y+1=0 is Parabola with (h,k)=(1,1),p=-3/16