What is (y^2}{16}-\frac{x^2)/4 =1 ?

The solution to (y^2}{16}-\frac{x^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=4,b=2

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(y^2}{16}-\frac{x^2)/4 =1

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

(h, k) = (0, 0), a = 4, b = 2

Solution steps

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

Rewrite

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 2

x^{2} - 2 x + 8 y + 9 = 0

x^{2} - 5 y = 0

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

y^{2} = 40 x

y^{2} = - 14 x

What is (y^2}{16}-\frac{x^2)/4 =1 ?
The solution to (y^2}{16}-\frac{x^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=4,b=2