What is the answer to solvefor D,hZ=(D(r^2-2h))/(3a) ?

The answer to solvefor D,hZ=(D(r^2-2h))/(3a) is D=(hZ*3a)/(r^2-2h);\quad a\ne 0,r^2-2h\ne 0

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solvefor D,hZ=(D(r^2-2h))/(3a)

solve for

D, h Z = \frac{D ( r ^{2} - 2 h )}{3 a}

D = \frac{h Z \cdot 3 a}{r ^{2} - 2 h}; a \neq = 0, r^{2} - 2 h \neq = 0

Solution steps

h Z = \frac{D ( r ^{2} - 2 h )}{3 a}

Switch sides

\frac{D ( r ^{2} - 2 h )}{3 a} = h Z

Multiply both sides by

3 a

D (r^{2} - 2 h) = h Z \cdot 3 a; a \neq = 0

Divide both sides by

r^{2} - 2 h; a \neq = 0, r^{2} - 2 h \neq = 0

D = \frac{h Z \cdot 3 a}{r ^{2} - 2 h}; a \neq = 0, r^{2} - 2 h \neq = 0

y < - x^{2}

x, x = 3600 q - 45 q (x)^{2}

y = 16 x^{2}

x^{2} - 6 x + 5 y - 11 = 0

\frac{25 y ^{2}}{400} - \frac{16 x}{400} = \frac{400}{400}

What is the answer to solvefor D,hZ=(D(r^2-2h))/(3a) ?
The answer to solvefor D,hZ=(D(r^2-2h))/(3a) is D=(hZ*3a)/(r^2-2h);\quad a\ne 0,r^2-2h\ne 0