What is 1=sqrt(x-0)^2+(y-1)^2 ?

The solution to 1=sqrt(x-0)^2+(y-1)^2 is Parabola with (h,k)=(1,1),p=-1/4

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1=sqrt(x-0)^2+(y-1)^2

1 = x - 0^{2} + (y - 1)^{2}

(h, k) = (1, 1), p = - \frac{1}{4}

Solution steps

1 = (x - 0)^{2} + (y - 1)^{2}

Rewrite

1 = (x - 0)^{2} + (y - 1)^{2}

in the standard form

4 (- \frac{1}{4}) (x - 1) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 1), p = - \frac{1}{4}

\frac{( x + 2 )}{16} + \frac{( y - 3 ) ^{2}}{49} = 1

y = - 0.005 (x)^{2} + 190

y^{2} - x - 16 = 0

(y - 3)^{2} = 16 (x - 6)

2 x^{2} + 3 y + 19 = 0

What is 1=sqrt(x-0)^2+(y-1)^2 ?
The solution to 1=sqrt(x-0)^2+(y-1)^2 is Parabola with (h,k)=(1,1),p=-1/4