What is (x+1)/(3+5)=(y+2)/(2+x+4) ?

The solution to (x+1)/(3+5)=(y+2)/(2+x+4) is Parabola with (h,k)=(-7/2 ,-89/32),p=2

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(x+1)/(3+5)=(y+2)/(2+x+4)

\frac{x + 1}{3 + 5} = \frac{y + 2}{2 + x + 4}

(h, k) = (- \frac{7}{2}, - \frac{89}{32}), p = 2

Solution steps

\frac{x + 1}{3 + 5} = \frac{y + 2}{2 + x + 4}

Rewrite

\frac{x + 1}{3 + 5} - \frac{y + 2}{2 + x + 4} = 0

in the standard form

4 \cdot 2 (y - (- \frac{89}{32})) = (x - (- \frac{7}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{2}, - \frac{89}{32}), p = 2

3 x^{2} + 12 x + y + 13 = 0

x^{2} + x - 5 y + 2 = 0

P (x) - 2 = 3 x^{2} - 1

x = 12 g (x, y) y 2

x^{2} + 6 x - 8 y - 1 = 0

What is (x+1)/(3+5)=(y+2)/(2+x+4) ?
The solution to (x+1)/(3+5)=(y+2)/(2+x+4) is Parabola with (h,k)=(-7/2 ,-89/32),p=2