What is the answer to solvefor g,g=g(x)^2-x ?

The answer to solvefor g,g=g(x)^2-x is g=-x/(1-x^2);\quad x\ne 1,x\ne-1

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solvefor g,g=g(x)^2-x

solve for

g, g = g (x)^{2} - x

g = - \frac{x}{1 - x ^{2}}; x \neq = 1, x \neq = - 1

Solution steps

g = g x^{2} - x

Move

g x^{2}

to the left side

g - g x^{2} = - x

Factor

g - g x^{2} : g (1 - x^{2})

g (1 - x^{2}) = - x

Divide both sides by

1 - x^{2}; x \neq = 1, x \neq = - 1

g = - \frac{x}{1 - x ^{2}}; x \neq = 1, x \neq = - 1

(x - 2) = (y - 5)^{2}

y = 2 x^{2} - 12 x + 26

x^{2} - 4 x + m (x) + 1 = 0

(x - 2)^{2} = - 4 y

y + 2 x^{2} - 6 = 0

What is the answer to solvefor g,g=g(x)^2-x ?
The answer to solvefor g,g=g(x)^2-x is g=-x/(1-x^2);\quad x\ne 1,x\ne-1