What is -f(x)=4(x)^2+3(x)-3 ?

The solution to -f(x)=4(x)^2+3(x)-3 is Parabola with (h,k)=(-3/8 , 57/16),p=-1/16

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-f(x)=4(x)^2+3(x)-3

- f (x) = 4 (x)^{2} + 3 (x) - 3

(h, k) = (- \frac{3}{8}, \frac{57}{16}), p = - \frac{1}{16}

Solution steps

- y = 4 x^{2} + 3 x - 3

Rewrite

- y = 4 x^{2} + 3 x - 3

in the standard form

4 (- \frac{1}{16}) (y - \frac{57}{16}) = (x - (- \frac{3}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{8}, \frac{57}{16}), p = - \frac{1}{16}

x = y^{2} - 3 y - 10

y = 4 (x - 2)^{2}

f (x) = - (x - 4)^{2} - 24

6 - 3 y - 4 x^{2} = 7 x + 3

f (x) - 4 = x^{(2)} - 2 x + 5

What is -f(x)=4(x)^2+3(x)-3 ?
The solution to -f(x)=4(x)^2+3(x)-3 is Parabola with (h,k)=(-3/8 , 57/16),p=-1/16