What is (x+7)^2=x^2+(y-5)^2 ?

The solution to (x+7)^2=x^2+(y-5)^2 is Parabola with (h,k)=(0,5),p= 7/2

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(x+7)^2=x^2+(y-5)^2

(x + 7)^{2} = x^{2} + (y - 5)^{2}

(h, k) = (0, 5), p = \frac{7}{2}

Solution steps

(x + 7)^{2} = x^{2} + (y - 5)^{2}

Rewrite

(x + 7)^{2} = x^{2} + (y - 5)^{2}

in the standard form

4 \cdot \frac{7}{2} (x - 0) = (y - 5)^{2}

Therefore parabola properties are:

(h, k) = (0, 5), p = \frac{7}{2}

2 \cdot \frac{x}{x - 3} + 2 (x - 3) = 28

y^{2} + 4 x - 9 = 0

\frac{( x - 5 )}{3} = \frac{3 x - 1}{5} + 2 E (x, y) y

(y + 3)^{2} = x

p^{2} = 20 - \frac{q}{5}

What is (x+7)^2=x^2+(y-5)^2 ?
The solution to (x+7)^2=x^2+(y-5)^2 is Parabola with (h,k)=(0,5),p= 7/2