What is ((x+5)^2)/(100)+((y-2^2))/(36)=1 ?

The solution to ((x+5)^2)/(100)+((y-2^2))/(36)=1 is Parabola with (h,k)=(-5,40),p=-25/36

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((x+5)^2)/(100)+((y-2^2))/(36)=1

\frac{( x + 5 ) ^{2}}{100} + \frac{( y - 2 ^{2} )}{36} = 1

(h, k) = (- 5, 40), p = - \frac{25}{36}

Solution steps

\frac{( x + 5 ) ^{2}}{100} + \frac{y - 2 ^{2}}{36} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{100} + \frac{y - 2 ^{2}}{36} = 1

in the standard form:

4 (- \frac{25}{36}) (y - 40) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, 40), p = - \frac{25}{36}

97 + a^{2} = b

f (x) = - 3 x^{2} + x + 9

5 x^{2} + 3 x + k (x) = 0

y + 1 = x (x + 4)

(y + 2) + 3 = (x + 1)^{2}

What is ((x+5)^2)/(100)+((y-2^2))/(36)=1 ?
The solution to ((x+5)^2)/(100)+((y-2^2))/(36)=1 is Parabola with (h,k)=(-5,40),p=-25/36