What is 1000n^2=980n^2+TA^2 ?

The solution to 1000n^2=980n^2+TA^2 is Parabola with (h,k)=(0,0),p=(A^2)/(80)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1000n^2=980n^2+TA^2

1000 n^{2} = 980 n^{2} + T A^{2}

(h, k) = (0, 0), p = \frac{A ^{2}}{80}

Solution steps

1000 n^{2} = 980 n^{2} + T A^{2}

Rewrite

1000 n^{2} = 980 n^{2} + T A^{2}

in the standard form:

4 \cdot \frac{A ^{2}}{80} (T - 0) = (n - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{A ^{2}}{80}

3 x^{2} + 24 x + 26 = 4 + 26 y

2 x^{2} + y = 8

(x + 3)^{2} = y + 4

2 x^{2} + y > 0

(x - 0) + (y - 8)^{2} = 25

What is 1000n^2=980n^2+TA^2 ?
The solution to 1000n^2=980n^2+TA^2 is Parabola with (h,k)=(0,0),p=(A^2)/(80)