What is (x^2}{81}-\frac{y^2)/9 =1 ?

The solution to (x^2}{81}-\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=9,b=3

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(x^2}{81}-\frac{y^2)/9 =1

\frac{x ^{2}}{81} - \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 9, b = 3

Solution steps

\frac{x ^{2}}{81} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{81} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{9 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 9, b = 3

9 x^{2} + 25 y^{2} = 225

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1

9 x^{2} - 25 y^{2} = 225

\frac{( x + 3 ) ^{2}}{16} + \frac{( y - 5 ) ^{2}}{25} = 1

x^{2} - 8 x + y^{2} + 2 y = - 16

What is (x^2}{81}-\frac{y^2)/9 =1 ?
The solution to (x^2}{81}-\frac{y^2)/9 =1 is Hyperbola with (h,k)=(0,0),a=9,b=3